Files
BoosAPI/desktop/libs/markstream-vue/test/math-inline-escaped-parens-duplicate.test.ts
boos e0a5f57793 feat(desktop): embed BoosAPI Desktop client as a subproject
Vendor the rebranded BoosAPI Desktop client (Tauri + Vue) into metapi as
a monorepo subdirectory under desktop/. Source only — node_modules,
dist, Cargo target and the upstream .git history are excluded.

desktop/ keeps its own independent Cargo workspace (desktop/src-tauri
with crates/*); it is not part of the backend boosapi crate, so a
`cargo check` at the metapi root still compiles only the backend. Build
the desktop app from desktop/src-tauri per desktop/README.md.

Note: app icons are still placeholder assets pending the final BoosAPI
logo. The updater signing keys live outside the repo and are not
included.
2026-06-22 11:32:57 +08:00

49 lines
1.5 KiB
TypeScript

import { getMarkdown, parseMarkdownToStructure } from 'stream-markdown-parser'
import { describe, expect, it } from 'vitest'
function walk(value: unknown, visit: (node: any) => void, seen = new WeakSet<object>()) {
if (!value)
return
if (typeof value !== 'object')
return
if (seen.has(value))
return
seen.add(value)
if (Array.isArray(value)) {
for (const item of value)
walk(item, visit, seen)
return
}
const node = value as any
if (typeof node.type === 'string')
visit(node)
for (const child of Object.values(node))
walk(child as any, visit, seen)
}
function collectText(nodes: unknown) {
const parts: string[] = []
walk(nodes, (node) => {
if (node.type === 'text' && typeof node.content === 'string')
parts.push(node.content)
})
return parts.join('')
}
describe('math inline - avoid duplicated text around \\( \\)', () => {
const md = getMarkdown('math-inline-escaped-parens-duplicate')
it('does not duplicate the text span when a \\( \\) pair is skipped as non-math', () => {
const input = String.raw`计算\( (\complement_{\text{R}}P)\cap M \)
求两个集合的交集,即取同时属于\( [0,1] \)和\( \left( \frac{1}{2},+\infty \right) \)的部分,得\\( \left( \frac{1}{2},1 \right] \\),对应选项A。`
const nodes = parseMarkdownToStructure(input, md)
const text = collectText(nodes)
const needle = '求两个集合的交集,即取同时属于( [0,1] )'
expect(text.split(needle).length - 1).toBe(1)
})
})