boos
e0a5f57793
Vendor the rebranded BoosAPI Desktop client (Tauri + Vue) into metapi as a monorepo subdirectory under desktop/. Source only — node_modules, dist, Cargo target and the upstream .git history are excluded. desktop/ keeps its own independent Cargo workspace (desktop/src-tauri with crates/*); it is not part of the backend boosapi crate, so a `cargo check` at the metapi root still compiles only the backend. Build the desktop app from desktop/src-tauri per desktop/README.md. Note: app icons are still placeholder assets pending the final BoosAPI logo. The updater signing keys live outside the repo and are not included.
90 lines
2.9 KiB
TypeScript
90 lines
2.9 KiB
TypeScript
import { describe, expect, it } from 'vitest'
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import { getMarkdown, parseMarkdownToStructure } from '../src'
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function collectTexts(n: any): string[] {
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if (!n)
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return []
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if (Array.isArray(n))
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return n.flatMap(collectTexts)
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if (typeof n === 'string')
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return [n]
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const texts: string[] = []
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if (n.type === 'text' && typeof n.content === 'string')
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texts.push(n.content)
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if (n.children && Array.isArray(n.children))
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texts.push(...n.children.flatMap(collectTexts))
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if (n.items && Array.isArray(n.items))
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texts.push(...n.items.flatMap(collectTexts))
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return texts
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}
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function countOccurrences(nodes: any, needle: string) {
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const allTexts = collectTexts(nodes).join('\n')
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return (allTexts.match(new RegExp(needle, 'g')) || []).length
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}
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describe('parseMarkdownToStructure - duplicate question rendering', () => {
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it('does not duplicate the question text when parsing mixed math/ce commands', () => {
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const md = getMarkdown()
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const markdown = `**当堂检测**：
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1. 下列物质属于酚的是（ ）
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A. $\ce{CH3CH2OH}$ B. $\ce{C6H5CH2OH}$ C. $\ce{}$ D. $\ce{HO-CH2-CH2OH}$
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**答案**：C`
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const nodes = parseMarkdownToStructure(markdown, md)
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const allTexts = collectTexts(nodes).join('\n')
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console.log('All texts:', JSON.stringify(allTexts, null, 2))
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// Count occurrences of the core question string
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expect(countOccurrences(nodes, '下列物质属于酚的是')).toBe(1)
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})
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const streamingCases = [
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{
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name: 'plain text prefix before $$ math',
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markdown: `第（1）题
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题干解析：本题考查利用导数求含参函数的极值，核心条件为函数 $$ f(x) = \\ln x - m + \\dfrac{m}{x} $$（$$ m \\in \\mathbb{R} $$）`,
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needle: '第（1）题',
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},
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{
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name: 'plain text prefix before $ math',
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markdown: `第（2）题
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已知函数 $f(x)=x^2$，求导数。`,
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needle: '第（2）题',
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},
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{
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name: 'plain text prefix before \\( \\) math',
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markdown: String.raw`第（3）题
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若 \(a+b=1\)，求 \(ab\) 的值。`,
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needle: '第（3）题',
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},
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{
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name: 'strong prefix before $$ math',
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markdown: `**第（4）题**
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题干解析：函数 $$x^2$$ 的图像。`,
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needle: '第（4）题',
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},
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{
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name: 'markdown link prefix before $ math',
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markdown: `[第（5）题](https://example.com)
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题干解析：函数 $x^2$ 的图像。`,
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needle: '第（5）题',
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},
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{
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name: 'inline html prefix before $$ math',
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markdown: `<span>第（6）题</span>
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题干解析：函数 $$x^2$$ 的图像。`,
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needle: '第（6）题',
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},
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] as const
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for (const testCase of streamingCases) {
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it(`does not duplicate the hardbreak prefix for ${testCase.name} while streaming`, () => {
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const md = getMarkdown()
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const nodes = parseMarkdownToStructure(testCase.markdown, md)
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expect(countOccurrences(nodes, testCase.needle)).toBe(1)
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})
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}
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})
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