feat(desktop): embed BoosAPI Desktop client as a subproject

Vendor the rebranded BoosAPI Desktop client (Tauri + Vue) into metapi as
a monorepo subdirectory under desktop/. Source only — node_modules,
dist, Cargo target and the upstream .git history are excluded.

desktop/ keeps its own independent Cargo workspace (desktop/src-tauri
with crates/*); it is not part of the backend boosapi crate, so a
`cargo check` at the metapi root still compiles only the backend. Build
the desktop app from desktop/src-tauri per desktop/README.md.

Note: app icons are still placeholder assets pending the final BoosAPI
logo. The updater signing keys live outside the repo and are not
included.
This commit is contained in:
boos
2026-06-22 11:32:57 +08:00
parent d9c78ecc73
commit e0a5f57793
2305 changed files with 449355 additions and 0 deletions
@@ -0,0 +1,40 @@
import { getMarkdown, parseMarkdownToStructure } from 'stream-markdown-parser'
import { describe, expect, it } from 'vitest'
const markdown = `- 代入数据:$c=0.75\\times10^3\\ \\text{J/(kg·℃)}$,$m=1.1\\ \\text{kg}$,$\\Delta t=40℃$
- 计算得:$Q_1=0.75\\times10^3\\ \\text{J/(kg·℃)}\\times1.1\\ \\text{kg}\\times40℃=3.3\\times 10^{4}\\ \\text{J}$
- 第(1)问:学生遗漏了比热容的数量级$10^3$,将$0.75\\times10^3\\ \\text{J/(kg·℃)}$错写为$0.75\\ \\text{J/(kg·℃)}$,导致计算出的$Q_1$错误。`
function collectMathNodes(node: any, mathNodes: any[] = []) {
if (!node)
return mathNodes
if (node.type === 'math_inline' || node.type === 'math_block')
mathNodes.push(node)
if (Array.isArray(node.children))
node.children.forEach(child => collectMathNodes(child, mathNodes))
if (Array.isArray(node.items))
node.items.forEach(child => collectMathNodes(child, mathNodes))
return mathNodes
}
describe('issue #378 parse regression', () => {
it('keeps the affected unit formulas as math nodes', () => {
const md = getMarkdown('issue-378-parse')
const nodes = parseMarkdownToStructure(markdown, md, { final: true }) as any[]
const mathNodes = nodes.flatMap(node => collectMathNodes(node))
expect(mathNodes.map(node => node.raw)).toEqual([
'$c=0.75\\times10^3\\ \\text{J/(kg·℃)}$',
'$m=1.1\\ \\text{kg}$',
'$\\Delta t=40℃$',
'$Q_1=0.75\\times10^3\\ \\text{J/(kg·℃)}\\times1.1\\ \\text{kg}\\times40℃=3.3\\times 10^{4}\\ \\text{J}$',
'$10^3$',
'$0.75\\times10^3\\ \\text{J/(kg·℃)}$',
'$0.75\\ \\text{J/(kg·℃)}$',
'$Q_1$',
])
})
})