feat(desktop): embed BoosAPI Desktop client as a subproject
Vendor the rebranded BoosAPI Desktop client (Tauri + Vue) into metapi as a monorepo subdirectory under desktop/. Source only — node_modules, dist, Cargo target and the upstream .git history are excluded. desktop/ keeps its own independent Cargo workspace (desktop/src-tauri with crates/*); it is not part of the backend boosapi crate, so a `cargo check` at the metapi root still compiles only the backend. Build the desktop app from desktop/src-tauri per desktop/README.md. Note: app icons are still placeholder assets pending the final BoosAPI logo. The updater signing keys live outside the repo and are not included.
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@@ -0,0 +1,40 @@
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import { getMarkdown, parseMarkdownToStructure } from 'stream-markdown-parser'
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import { describe, expect, it } from 'vitest'
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const markdown = `- 代入数据:$c=0.75\\times10^3\\ \\text{J/(kg·℃)}$,$m=1.1\\ \\text{kg}$,$\\Delta t=40℃$
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- 计算得:$Q_1=0.75\\times10^3\\ \\text{J/(kg·℃)}\\times1.1\\ \\text{kg}\\times40℃=3.3\\times 10^{4}\\ \\text{J}$
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- 第(1)问:学生遗漏了比热容的数量级$10^3$,将$0.75\\times10^3\\ \\text{J/(kg·℃)}$错写为$0.75\\ \\text{J/(kg·℃)}$,导致计算出的$Q_1$错误。`
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function collectMathNodes(node: any, mathNodes: any[] = []) {
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if (!node)
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return mathNodes
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if (node.type === 'math_inline' || node.type === 'math_block')
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mathNodes.push(node)
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if (Array.isArray(node.children))
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node.children.forEach(child => collectMathNodes(child, mathNodes))
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if (Array.isArray(node.items))
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node.items.forEach(child => collectMathNodes(child, mathNodes))
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return mathNodes
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}
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describe('issue #378 parse regression', () => {
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it('keeps the affected unit formulas as math nodes', () => {
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const md = getMarkdown('issue-378-parse')
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const nodes = parseMarkdownToStructure(markdown, md, { final: true }) as any[]
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const mathNodes = nodes.flatMap(node => collectMathNodes(node))
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expect(mathNodes.map(node => node.raw)).toEqual([
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'$c=0.75\\times10^3\\ \\text{J/(kg·℃)}$',
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'$m=1.1\\ \\text{kg}$',
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'$\\Delta t=40℃$',
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'$Q_1=0.75\\times10^3\\ \\text{J/(kg·℃)}\\times1.1\\ \\text{kg}\\times40℃=3.3\\times 10^{4}\\ \\text{J}$',
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'$10^3$',
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'$0.75\\times10^3\\ \\text{J/(kg·℃)}$',
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'$0.75\\ \\text{J/(kg·℃)}$',
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'$Q_1$',
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])
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})
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})
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