feat(desktop): embed BoosAPI Desktop client as a subproject

Vendor the rebranded BoosAPI Desktop client (Tauri + Vue) into metapi as
a monorepo subdirectory under desktop/. Source only — node_modules,
dist, Cargo target and the upstream .git history are excluded.

desktop/ keeps its own independent Cargo workspace (desktop/src-tauri
with crates/*); it is not part of the backend boosapi crate, so a
`cargo check` at the metapi root still compiles only the backend. Build
the desktop app from desktop/src-tauri per desktop/README.md.

Note: app icons are still placeholder assets pending the final BoosAPI
logo. The updater signing keys live outside the repo and are not
included.
This commit is contained in:
boos
2026-06-22 11:32:57 +08:00
parent d9c78ecc73
commit e0a5f57793
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import { describe, expect, it } from 'vitest'
import { getMarkdown, parseMarkdownToStructure } from '../src'
function collectTexts(n: any): string[] {
if (!n)
return []
if (Array.isArray(n))
return n.flatMap(collectTexts)
if (typeof n === 'string')
return [n]
const texts: string[] = []
if (n.type === 'text' && typeof n.content === 'string')
texts.push(n.content)
if (n.children && Array.isArray(n.children))
texts.push(...n.children.flatMap(collectTexts))
if (n.items && Array.isArray(n.items))
texts.push(...n.items.flatMap(collectTexts))
return texts
}
function countOccurrences(nodes: any, needle: string) {
const allTexts = collectTexts(nodes).join('\n')
return (allTexts.match(new RegExp(needle, 'g')) || []).length
}
describe('parseMarkdownToStructure - duplicate question rendering', () => {
it('does not duplicate the question text when parsing mixed math/ce commands', () => {
const md = getMarkdown()
const markdown = `**当堂检测**:
1. 下列物质属于酚的是( )
A. $\ce{CH3CH2OH}$ B. $\ce{C6H5CH2OH}$ C. $\ce{}$ D. $\ce{HO-CH2-CH2OH}$
**答案**:C`
const nodes = parseMarkdownToStructure(markdown, md)
const allTexts = collectTexts(nodes).join('\n')
console.log('All texts:', JSON.stringify(allTexts, null, 2))
// Count occurrences of the core question string
expect(countOccurrences(nodes, '下列物质属于酚的是')).toBe(1)
})
const streamingCases = [
{
name: 'plain text prefix before $$ math',
markdown: `第(1)题
题干解析:本题考查利用导数求含参函数的极值,核心条件为函数 $$ f(x) = \\ln x - m + \\dfrac{m}{x} $$($$ m \\in \\mathbb{R} $$)`,
needle: '第(1)题',
},
{
name: 'plain text prefix before $ math',
markdown: `第(2)题
已知函数 $f(x)=x^2$,求导数。`,
needle: '第(2)题',
},
{
name: 'plain text prefix before \\( \\) math',
markdown: String.raw`第(3)题
若 \(a+b=1\),求 \(ab\) 的值。`,
needle: '第(3)题',
},
{
name: 'strong prefix before $$ math',
markdown: `**第(4)题**
题干解析:函数 $$x^2$$ 的图像。`,
needle: '第(4)题',
},
{
name: 'markdown link prefix before $ math',
markdown: `[第(5)题](https://example.com)
题干解析:函数 $x^2$ 的图像。`,
needle: '第(5)题',
},
{
name: 'inline html prefix before $$ math',
markdown: `<span>第(6)题</span>
题干解析:函数 $$x^2$$ 的图像。`,
needle: '第(6)题',
},
] as const
for (const testCase of streamingCases) {
it(`does not duplicate the hardbreak prefix for ${testCase.name} while streaming`, () => {
const md = getMarkdown()
const nodes = parseMarkdownToStructure(testCase.markdown, md)
expect(countOccurrences(nodes, testCase.needle)).toBe(1)
})
}
})